📘 Complete Chapter Notes (Work, Energy and Power)
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Introduction to Work, Energy and Power
Work, energy, and power are fundamental concepts in physics that describe how forces cause motion, how energy is transferred and transformed, and how quickly work is done.
When we push a box, lift a book, or run up stairs, we're doing work. This chapter explores the relationship between force, displacement, and energy, and how these concepts are interconnected through the principle of conservation of energy.
Key Concepts Covered
- Definition and calculation of work
- Different forms of energy (kinetic, potential)
- Law of conservation of energy
- Power and efficiency
- Renewable and non-renewable energy sources
- Applications of energy in daily life
- Environmental impact of energy production
Important Definitions
Work: Work is said to be done when a force acts on an object and moves it through some distance. Mathematically, \( W = F \times S \).
Energy: The ability of a body to do work. The SI unit of energy is joule (J).
Kinetic Energy: The energy that a body possesses by virtue of its motion. \( E_k = \frac{1}{2}mv^2 \).
Potential Energy: The energy that a body possesses by virtue of its position or deformation. \( E_p = mgh \).
Power: The time rate of doing work. \( P = \frac{W}{t} \). The SI unit of power is watt (W).
Efficiency: The ratio of useful output energy to the total input energy, often expressed as a percentage.
Conservation of Energy: Energy cannot be created or destroyed; it may be transformed from one form to another, but the total amount of energy never changes.
Key Formulas
Work Done
\[W = F \times S\]Where \( W \) is work, \( F \) is force, and \( S \) is displacement
Work Done at an Angle
\[W = FS \cos \theta\]Where \( \theta \) is the angle between force and displacement
Kinetic Energy
\[E_k = \frac{1}{2}mv^2\]Where \( m \) is mass and \( v \) is velocity
Potential Energy
\[E_p = mgh\]Where \( m \) is mass, \( g \) is gravitational acceleration, and \( h \) is height
Power
\[P = \frac{W}{t}\]Where \( P \) is power, \( W \) is work, and \( t \) is time
Efficiency
\[\text{Efficiency} = \frac{\text{Useful output energy}}{\text{Total input energy}} \times 100\%\]Detailed Chapter Content
1. Work
Work is done when a force causes displacement in the direction of the force. If there is no displacement, no work is done regardless of how much force is applied.
Special cases:
- When \( \theta = 0^\circ \), \( \cos 0^\circ = 1 \), so \( W = FS \) (maximum work)
- When \( \theta = 90^\circ \), \( \cos 90^\circ = 0 \), so \( W = 0 \) (no work done)
2. Energy
Energy exists in many forms and can be converted from one form to another. The two basic forms of mechanical energy are:
3. Forms of Potential Energy
- Gravitational Potential Energy: Energy due to position relative to Earth
- Elastic Potential Energy: Energy stored in compressed or stretched springs
- Chemical Potential Energy: Energy stored in chemicals (batteries, fuels)
- Nuclear Energy: Energy stored in atomic nuclei
4. Conservation of Energy
The total energy in an isolated system remains constant. Energy can change from one form to another but cannot be created or destroyed.
Example: A falling object converts potential energy to kinetic energy, but the total mechanical energy remains constant (ignoring air resistance).
5. Energy Sources
6. Power and Efficiency
Power measures how quickly work is done. Efficiency measures how effectively energy is converted from one form to another.
No system can have 100% efficiency due to energy losses (mainly as heat from friction).
7. Environmental Impact of Energy Production
- Fossil fuels: Produce smoke, CO₂, and heat pollution
- Nuclear energy: Risk of radiation leakage and waste disposal problems
- Renewable sources: Generally cleaner but may have other environmental impacts
- Thermal pollution: Waste energy ends up as heat, contributing to global warming
Sample Problems
Given:
A force of 10 N is applied to move a box through a distance of 5 m in the direction of the force.
Solution:
Using the formula \( W = F \times S \):
\( W = 10 \, \text{N} \times 5 \, \text{m} = 50 \, \text{J} \)
The work done is 50 joules.
Given:
A slow-moving car (mass = 1000 kg, velocity = 5 m/s) and a fast-moving motorcycle (mass = 200 kg, velocity = 20 m/s).
Solution:
Car's kinetic energy: \( E_k = \frac{1}{2} \times 1000 \times (5)^2 = 12,500 \, \text{J} \)
Motorcycle's kinetic energy: \( E_k = \frac{1}{2} \times 200 \times (20)^2 = 40,000 \, \text{J} \)
The motorcycle has more kinetic energy despite having less mass, due to its higher velocity.
Given:
Force F₁ does 5 J of work in 10 s. Force F₂ does 3 J of work in 5 s.
Solution:
Power of F₁: \( P_1 = \frac{5}{10} = 0.5 \, \text{W} \)
Power of F₂: \( P_2 = \frac{3}{5} = 0.6 \, \text{W} \)
Force F₂ delivers more power.
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